2[(3x+2)+4]+2(x-2)=120

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Solution for 2[(3x+2)+4]+2(x-2)=120 equation:


Simplifying
2[(3x + 2) + 4] + 2(x + -2) = 120

Reorder the terms:
2[(2 + 3x) + 4] + 2(x + -2) = 120

Remove parenthesis around (2 + 3x)
2[2 + 3x + 4] + 2(x + -2) = 120

Reorder the terms:
2[2 + 4 + 3x] + 2(x + -2) = 120

Combine like terms: 2 + 4 = 6
2[6 + 3x] + 2(x + -2) = 120
[6 * 2 + 3x * 2] + 2(x + -2) = 120
[12 + 6x] + 2(x + -2) = 120

Reorder the terms:
12 + 6x + 2(-2 + x) = 120
12 + 6x + (-2 * 2 + x * 2) = 120
12 + 6x + (-4 + 2x) = 120

Reorder the terms:
12 + -4 + 6x + 2x = 120

Combine like terms: 12 + -4 = 8
8 + 6x + 2x = 120

Combine like terms: 6x + 2x = 8x
8 + 8x = 120

Solving
8 + 8x = 120

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 8x = 120 + -8

Combine like terms: 8 + -8 = 0
0 + 8x = 120 + -8
8x = 120 + -8

Combine like terms: 120 + -8 = 112
8x = 112

Divide each side by '8'.
x = 14

Simplifying
x = 14

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